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x^2+6.25x+5.25=0
a = 1; b = 6.25; c = +5.25;
Δ = b2-4ac
Δ = 6.252-4·1·5.25
Δ = 18.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.25)-\sqrt{18.0625}}{2*1}=\frac{-6.25-\sqrt{18.0625}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.25)+\sqrt{18.0625}}{2*1}=\frac{-6.25+\sqrt{18.0625}}{2} $
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